Suppose a 95% confidence interval for the average amount of weight loss on a diet program for males is between 13. 0 and 18. 0 pounds. These results were based on a sample of 42 male participants who were deemed to be overweight at the start of the 4-month study. What is the margin of error for this study?

Respuesta :

The standard error of the sample mean is 1.237.

How to calculate the standard error of the sample mean?

Given,

c = 95% = 0.95

n = 42

lower limit = 13.0

upper limit = 18.0

Since standard deviation population is unknown, we use this formula to calculate standard error.

standard error = margin of error / tα/2,d.f

First, we calculate the t distribution value

tα/2,d.f = t₍₁₋₀.₉₅₎/₂,₄₂₋₁

= t₀.₀₂₅,₄₁

To find the value use t table. So,  t₀.₀₂₅,₄₁ = 2.0195

Next, we calculate the margin of error

margin of error = (upper limit - lower limit)/2

= (18.0 - 13.0)/2

= 5/2

= 2.5

Now, we can calculate the standard error. So,

standard error = 2.5 / 2.0195

= 1.237

Thus, the standard error of the sample mean is 1.237

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