If 3.66 g of CuO3 is dissolved in water to make a 0.330 m solution, the volume of the solution is 65 mL.
Concentration = [tex]\frac {Moles of solute} {Volume of solution}[/tex]
and thus volume of solution is = [tex]\frac {molese of solute} {concentration}[/tex]
=[tex]\frac {3.66 g } {187.56 g/mol}[/tex] × [tex]\frac {1} {0.330 mol/L}[/tex]
= 0.065 L
now we know that 1 L = 1000 mL
so 0.065 L = [tex]\frac{0.065}{1}[/tex] × 1000
= 65 mL
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