The volume of the water is 2450 ml.
The dilution equation :
M₁ . V₁ = M₂ . V₂
Where, M₁ = Molarity of H₂SO₄ = 15.0 m
V₁ = Volume of H₂SO₄ = 50.0 ml
M₂ = Molarity of final solution = 0.300 m
V₂ = Volume of final solution = ?
now, putting the values ,
15.0 × 50.0 = 0.300 ×V₂
V₂ = 2500 ml of final solution
now, volume of water = V₂ - V₁
Volume of water = 2500 - 50
Volume of water = 2450 ml
We have to add 2450 ml of the water to 50.0 ml of a 15.0 m H₂SO₄ solution to give a final concentration of 0.300 m.
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