he simplest form of quadratic equation 6y² + 5y - 4 is y = 0.5 or y = −1.33333 or in fraction y = 6 / 12 or y = −16/12.
How to solve a quadratic equation using the Quadratic Formula.
- Write the quadratic equation in standard form, ax² + bx + c = 0. Identify the values of a, b, c.
- Write the Quadratic Formula. Then substitute in the values of a, b, c.
- Simplify.
- Check the solutions.
6y² + 5y - 4
using the Quadratic Formula where a = 6, b = 5, and c = -4
y =−b±(√b2−4ac) / (√2a)
y =−5±(√5²−4(6)(−4)) / √(2(6))
y =−5±(√25−(−96)) / √12
y =−5± (√121 / √12
The discriminant b²−4ac>0. So, there are two real roots.
Simplify the radical:
y = (-5 ± 11) /12
y = 6/12 y =16/12
which becomes
y = 0.5
y = −1.33333
Hence, the simplest form of quadratic equation 6y² + 5y - 4 is y = 0.5 or y = −1.33333.
To know more about quadratic equations check the given link below:
https://brainly.com/question/1214333
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