Respuesta :

[tex]\bf \begin{cases} f(x) = x^2 + 1\\\\ g(x) = 3x + 1 \end{cases}\quad \begin{cases} f(1)=\boxed{1}^2+1\to &\boxed{?}\\\\ g(4)=3(\boxed{4})+1\to &\boxed{?} \end{cases} \\\\\\ 2f(1)=2\cdot \boxed{?}\qquad \qquad 3g(4)=3\cdot \boxed{?}[/tex]
2f(1)+3g(4)=43

2*(1^2+1)=4
3*(3(4)+1)=39

4+39=43