There is a 2.1% chance that a random sample of 40 expectant mothers will have a mean weight increase of 16 pounds or greater if the mean second trimester weight gain for all expectant mothers is 14 pounds
Given:
In the question;
Suppose that CHDS finds the average weight increase in the second trimester is 14 pounds. Suppose also that, in 2015, a random sample of 40 expectant mothers have mean weight increase of 16 pounds in the second trimester, with a standard deviation of 6 pounds. At the 5% significance level, we can conduct a one-sided T-test to see if the mean weight increase in 2015 is greater than 14 pounds. Statistical software tells us that the p-value = 0.021.
Now, According to the question:
Since we have to test that whether the mean weight is greater than 14 pounds, so test is right tailed and if ta is the value of test static then p-value is P(t> t_a ) . Where t_a={16-14\over 6/\sqrt {40}} .
Now p-value is 0.021.
So, the correct conclusion is:
There is a 2.1% chance that a random sample of 40 expectant mothers will have a mean weight increase of 16 pounds or greater if the mean second trimester weight gain for all expectant mothers is 14 pounds
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