Jan and Wayne went to the store to buy some groceries. Jan bought 2 cans of corn beef hash and 3 cans of creamed chipped beef for $4.95. Wayne bought 3 cans of corn beef hash and 2 cans of creamed chipped beef for $5.45. Let H represent the price of a can of corn beef hash, and C represent the price of a can of creamed chipped beef. solve for H and C

Respuesta :

You can solve this by using the system of equations.
Jan - 4.95 = 2H + 3C
Wayne - 5.45 = 3H + 2C

Use elimination.
-3(2H + 3C = 4.95)
2(3H + 2C = 5.45)

Solve. And you'll get:
-6H + (-9C) = -14.85
6H + 4C = 10.9

Cross out -6H and 6H because they cancel out. And you're left with:
-9C = -14.85
4C = 10.9

Add -9C with 4C, and -14.85 with 10.9.
-5C = -3.95

Divide each side with -5.
C = $0.79

Now to figure out what H is, just substitute the C in one of the equations with 0.79.
5.45 = 3H + 2(0.79)
5.45 = 3H + 1.58
-1.58            -1.58
3.87 = 3H
3.87/3 = 3/3(H)
1.29 = H

Finished!

The price of a can of creamed chipped beef is $ 0.79 and the price of a can of corn beef hash is h=1.29.

You can solve this by using the system of equations.

Jan - 4.95 = 2H + 3C

Wayne - 5.45 = 3H + 2C

What is the elimination method?

The elimination method is adding or subtracting the equations to get an equation in one variable.

Use the elimination method

-3(2H + 3C = 4.95)...(1)

2(3H + 2C = 5.45)...(2)

Solve equation (1)

-6H + (-9C) = -14.85

Now we get,

-6H + (-9C) = -14.85

6H + 4C = 10.9

The cancel out -6H and 6H

-9C = -14.85

4C = 10.9

Add -9C with 4C, and -14.85 with 10.9.

-5C = -3.95

Divide each side with -5.

C = $0.79

Now to figure out what H is by substituting the C in one equation with 0.79.

5.45 = 3H + 2(0.79)

5.45 = 3H + 1.58

Isolate H from both sides.

Subtracting 1.58 from both sides.

3.87 = 3H

3.87/3 = 3/3(H)

1.29 = H

Therefore, the price of a can of corn beef hash is h=1.29.

The price of a can of creamed chipped beef is $ 0.79.

To learn more about the elimination method visit:

https://brainly.com/question/8650555