For the following exercises, find the maximum rate of change of f at the given point and the direction in which it occurs. f(x, y) = xe-y, (1, 0)

Respuesta :

The maximum rate of change of f at the given point is 0.3678

Rate of change

Rate of change defined as the percentage change in value over a defined period of time, and it represents the momentum of a variable.

Given,

Here we the function  f(x, y) = [tex]xe^{-y}[/tex], (1, 0)

Now, we need to find the the maximum rate of change of f at the given point.

We know that, the average rate of change of f(x) on the interval [a, b] is written as,

=> f(x) = (fb) - f(a)/ b - a

Here the value of a = 1 and b = 0.

So, apply the values on the function to solve it,

f(1,1) = 1e⁻¹

f(1,1) = 1 x 0.3678

f(1,1) = 0.3678

Similarly, the value of f(0,0) is,

=> f(0,0) = 0e⁰

=> f(0,0) = 0 x 1

=> f(0,0) = 0

So, the rate of change is,

=> R = 0 - 0.3687/0-1

=> R = 0.3678.

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