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using the illustration in question 15, what would be the ip address of e0 if you were using the first subnet? the network id is 192.168.10.0/28, and you need to use the last available ip address in the range. again, the 0 subnet should not be considered valid for this question.

Respuesta :

The IP address of E0 if you were using the first subnet is 192.168.10.142

A /28 is a 255.255.255.240 mask. Let's count to the ninth subnet (we need to find the broadcast address of the eighth subnet, so we need to count to the ninth subnet). Starting at 16 (remember, the question stated that we will not use subnet zero, so we start at 16, not 0), 16, 32, 48, 64, 80, 96, 112, 128, 144.

The eighth subnet is 128 and the next subnet is 144, so our broadcast address of the 128 subnet is 143. This makes the host range 129-142. 142 is the last valid host.

Therefore, the IP address of E0 if you were using the first subnet is 192.168.10.142

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