To resolve the issue, we'll apply the moments' principle. According to the question, the wrench must exert 90 Nm of torque on the bolt. The angle at which the force acts (53o to the wrench) and the length of the lever arm (30 cm) are provided.
Before moving on to the computations themselves, a conversion. The wrench's length is specified in centimeters, which must be converted to meters:
30cm=30×10−2m=0.30m
Get an expression for the vertical component of the force now using trigonometry. The equation is Fv=Fsin53 since the vertical component is the reverse of the 53o angle.
The vertical component of the force is multiplied by the lever arm to produce the moment of the force (0.30 m).Keep in mind that the force must produce a 90 Nm torque, which I will enter on the left-hand side of the equation.
Calculation:
\s90=Fv⋅0.30=Fsin53⋅0.30
F=90sin530.30=375 N=376N, rearrange for F, and solve.
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