Respuesta :
The work that must be done by the frictional force in slowing a 1000 kg car from 26.1 m/s to a stop is 3.41 x 10⁵ J
Work
Work in physics is the amount of energy given to move an object.
The magnitude of the work of an object is equal to the kinetic energy experienced by the object.
So,
W = KE
W = ½ mv²
We have,
Mass of the car (m) = 1000 kg
Deceleration (v) = 26.1 m/s
Now, calculate the work that must be done:
W = KE
= ½ mv²
= ½ (1000) (26.1)²
= 340,605 = 3.4 x 10⁵ J
Learn more about work here: https://brainly.com/question/26152883
#SPJ4
