The equation of the line that passes through the point (8,2) and is parallel to the line x+4y = 28 is y = -x/4+4.
According to the question,
We have the following information;
Point thorough which line is passing = (8,2)
Equation of the line:
x+4y = 28
Now, we will convert this equation into the slope-intercept form:
4y = -x+28
Dividing by 4 on both sides of the equation:
y = -x/4+28/4
y = -x/4+7
Slope of the line = -1/4
We know that the following formula is used to find the equation of the line:
(y-y') = m(x-x')
(y-2) = -1/4(x-8)
y-2 = -x/4+2
Adding 2 on both sides:
y = -x/4+4
Hence, the equation of the line that passes through the point (8,2) and is parallel to the line x+4y = 28 is y = -x/4+4.
To know more about equation of the line here
https://brainly.com/question/21511618
#SPJ4
