a) a constant head permeability test was performed on a 35 cm2 (cross sectional area) soil sample. the length of the sample was 30 cm, and a 25 cm head difference was applied during testing. if 18 cm3 of water was collected over 80 sec, calculate the coefficient of permeability of the soil. (b) in a falling head permeability test,the head fell from 48 to 22 cm, in 6 minutes. the cross-sectional area of the soil sample is 60 cm2,and the length was 12 cm. if the area of the standpipe was 0.7 cm2, compute the coefficient of permeability of the soil.

Respuesta :

The value of the coefficient of permeability  is 1.6 × m/sec or 1.6 × cm/sec.

What is the value of coefficient of permeability ?

Length = 6 cm

   Area of cross-section = 50

   Quantity of water = 500 ml

   Time taken to flow = 15 mins = 15 × 60 secs = 900 secs

   Constant Head = 40 cm

The value of the coefficient of permeability.

The formula to find the coefficient of permeability is given by,

⇒ q = k×i×A

q = Q/t and i = (H/L) on substituting for "q" and "i" in the above equation we get,

Q/t = k(H/L)A

rearranging the above equation in terms of "k" we get,

⇒k = (Q×L)/(A×t×H)  → {equation 1}

Where "k" is the coefficient of permeability, "H" is the head constant, "A" is the area of cross-section, "L" is the length, "t" is the time taken to flow, and "Q" is the quantity of water.

On substituting the given values in equation 1 we get,

⇒ k = (500×6)/(50×900×40) {multiplying the terms}

⇒ k = 3000/18000 {dividing the terms}

⇒ k = 0.0016 = 1.6 × cm/sec or 1.6 × m/sec.

The value of the coefficient of permeability = 1.6 × m/sec or 1.6 × cm/sec

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