Answer: 0.077 M
Explanation:
Expression for rate law for first order kinetics is given by:
[tex]k=\frac{2.303}{t}\log\frac{a}{a-x}[/tex]
where,
k = rate constant = [tex]0.241minute^{-1}[/tex]
t = time taken for decay process = 10 minutes
a = initial amount of the reactant= 0.859 M
a - x = amount left after decay process =?
Putting values in above equation, we get:
[tex]0.241 minutes^{-1}=\frac{2.303}{10.0}\log\frac{0.859}{a-x}[/tex]
[tex](a-x)=0.077M[/tex]
Thus the concentration of a after 10.0 minutes is 0.077 M.
