contestada

speedometer readings for a motorcycle at 12-seconds intervals are given in the table. (a) estimate the distance, in feet, traveled by the motorcycle during the time interval from 0 to 60 seconds using the velocities at the beginning of the time intervals. (b) give another estimate using the velocities at the end of the time periods.

Respuesta :

dirayake

Step-by-step explanation:

Each interval is 12 seconds wide. If we use the beginning velocity to estimate the distance in the first interval, we get

12 sec * 22 ft/sec = 264 ft

If we use the ending velocity in the first interval, we get

12 sec * 24 ft/sec = 288 ft

Adding all the left-hand velocities,

12*(22 + 24 + 26 + 20 + 22) = 12*114 = 1368

If we use the ending velocities, we get

12*(24 + 26 + 20 + 22 + 29) = 12*121 = 1452

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