The leg of a right triangle is 3 units and the hypotenuse is 11 units. What is the length, in units, of the other leg of the triangle

pythagorean theorem (or however it is spelled)

a^2 + b^2 = c^2...where a and b are the legs and c is the hypotenuse

3^2 + b^2 = 11^2
9 + b^2 = 121
b^2 = 121 - 9
b^2 = 112...take the square root of both sides, eliminating the ^2
b = square root of 112
b = 10.58 <=== the other leg of the triangle

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swapnalimalwadeVT swapnalimalwadeVT · Answer 2 · 2022-04-26T09:53:03+02:00

The leg of a right triangle is 3 units and the hypotenuse is 11 units then the other leg of the triangle is 10.58 units.

The leg of a right triangle is 3 units and,

The hypotenuse is 11 units.

What is the pythagorean theorem?

[tex]a^2 + b^2 = c^2[/tex]

Where a and b are the legs and c is the hypotenuse

Therefore plug the given value in the above formula

leg = 3 units and, hypotenuse =11 units

Therefore we get,

[tex]3^2 + b^2 = 11^2[/tex]

[tex]9 + b^2 = 121[/tex]

[tex]b^2 = 121 - 9[/tex]

[tex]b^2 = 112[/tex]

Take the square root of both sides, eliminating the square.

[tex]b = \sqrt{112}[/tex]

[tex]b = 10.58[/tex]

The other leg of the triangle is 10.58 units.

To learn more about the right angle triangle visit:

https://brainly.com/question/2028228