Respuesta :
Answer:
The probability that a student plays either basketball or soccer is 19% or 0.19.
Step-by-step explanation:
Let A be the event that student play basketball and B be the event that student play soccer.
[tex]P(A)=8\%[/tex]
[tex]P(B)=14\%[/tex]
It is given that 6 students play on both teams.
[tex]P(A\cap B)=\frac{6}{200}\times 100=3\%[/tex]
We have to find the probability that a student plays either basketball or soccer.
[tex]P(A\cup B)=P(A)+P(B)-(A\cap B)[/tex]
[tex]P(A\cup B)=8\%+14\%-3\%[/tex]
[tex]P(A\cup B)=19\%[/tex]
Therefore the probability that a student plays either basketball or soccer is 19% or 0.19.
Answer:
19%
Step-by-step explanation:
just took my final ( A P E X )
