Respuesta :
According to Avogadro's law, 1 mole ,i.e., 6.2 * 10^23 particles of
every substance have mass equal to its molecular mass in grams. Since
the molecular mass of CuSO4 is 80 grams. It means 6.2 * 10^23 particles
of CuSO4 have a mass of 80 grams. Now u can calculate the mass of 3.36 *
10^23 particles by unitary method 3.36 * 10^23 *80/6.23 * 10^23 grams
Answer:
The weight in grams of [tex]3.36\times10^{23}[/tex] molecules of copper sulfate is 89.023 g.
Step-by-step explanation:
Given : Molecules of copper sulfate [tex]3.36\times10^{23}[/tex]
To find : What is the weight in grams of [tex]3.36\times10^{23}[/tex] molecules of copper sulfate?
Solution :
Molar mass of copper sulfate ([tex]CuSO_4[/tex])
Cu=63.5
S=32
O=16
[tex]CuSO_4=63.5+32+4\times16= 159.5 g[/tex]
We know, that 1 mole = Avogadro number
1 mole = [tex]6.02\times 10^{23}[/tex] molecules
[tex]6.02\times10^{23}[/tex] molecule weigh = 159.5 g
1 molecule weigh = [tex]\frac{159.5}{6.02\times10^{23}}[/tex] g
So, [tex]3.36\times10^{23}[/tex] molecule weigh = [tex]\frac{159.5\times3.36\times10^23}{6.02\times10^{23}}[/tex] g
[tex]=\frac{159.5\times3.36}{6.02}[/tex] g
[tex]=\frac{535.92}{6.02}[/tex] g
[tex]=89.023[/tex] g
Therefore, The weight in grams of [tex]3.36\times10^{23}[/tex] molecules of copper sulfate is 89.023 g.
