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What is the equation of the graphed line written in standard form?

x – 4y = 4
x + 4y = 4
y = x – 1
y = –x – 1

What is the equation of the graphed line written in standard form x 4y 4 x 4y 4 y x 1 y x 1 class=

Respuesta :

Setor9
First of all, standard form means it should be this form ax+by=c
The equation for the line is
y= 1/4x-1========>Multiply each term by 4
y (4) = 1/4(4)x-1(4)
4y = 4/4x-4
4y=x-4=========>Subtract x from both sides
4y-x=x-x-4

4y-x=-4 OR X-4Y=4
Your answer is A.

calculista

we know that

The equation of the line in standard form is equal to

[tex]Ax+By=C[/tex]

where

A is a positive integer

B and C are integers

Step 1

Find the slope of the graphed line

we have

[tex]A(0,-1)\ B(4,0)[/tex]

The slope of the line is equal to

[tex]m=\frac{y2-y1}{x2-x1}[/tex]

Substitute the values

[tex]m=\frac{0+1}{4-0}[/tex]

[tex]m=\frac{1}{4}[/tex]

Step 2

Find the equation of the line in slope-intercept form

the equation of the line in slope-intercept form is equal to

[tex]y=mx+b[/tex]

where

m is the slope

b is the value of the y-intercept

In this problem we have

[tex]m=\frac{1}{4}[/tex]

[tex]b=-1[/tex] ------> see the graph

substitute

[tex]y=\frac{1}{4}x-1[/tex]

Step 3

Convert to standard form

Multiply by [tex]4[/tex] both sides

[tex]4y=x-4[/tex]

[tex]x-4y=4[/tex]

therefore

the answer is the option

[tex]x-4y=4[/tex]


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