Respuesta :
OK if we said the the allel for smooth is (S ) and it is dominant and the allel for constricted is (s) and it is recessive , so we started by mating two pure pea plant one smooth and one constricted the offspring would have a genotype of (Ss) and it'S phenotype is smooth, and if that offspring did self pollination it will produce 4 offsprings with genotype as follow: 1 (SS) : 2 (Ss ) : 1 (ss) so there would be 3 smooth and one constricted which will be the last one (ss )
Answer:
There is only one offspring with homozygous alleles (SS) for the smooth pod trait out of the total four offspring. The frequency of this offspring with homozygous alleles (SS) for the smooth pod trait is
[tex]\frac{1}{4} * 100\\25[/tex]%
Explanation:
First Cross -
Let us assume that the genotype of parents in the first cross is
Smooth pod parent - SS
Constricted pod Parent - ss
Offspring produced after first cross are as shown in the punnet square below -
S S
s Ss Ss
s Ss Ss
All the offsprings are heterozygous (Ss) smooth
Second Cross -
The second cross is being carried between the two offsprings (Ss)
Offspring produced after second cross are as shown in the punnet square below -
S s
S SS Ss
s Ss ss
SS - homozygous smooth pod offsprings
Ss - heterozygous smooth pod offsprings
ss - homozygous constricted pod offsprings
There is only one offspring with homozygous alleles (SS) for the smooth pod trait out of the total four offspring. The frequency of this offspring with homozygous alleles (SS) for the smooth pod trait is
[tex]\frac{1}{4} * 100\\25[/tex]%