Two small planes leave Sacramento and LA, which are 380 miles apart, and travel toward each other. If one plane travels 30 miles per hour faster than the other plane and they meet in an hour, what are their respective speeds?

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Answer:

The faster plane is 205 mph and the slower plane is 175 mph

Step-by-step explanation:

that is you answer

When the two bodies travel at the same direction, the relative speed of the two bodies is the sum of the speed of both the bodies.The speed of the plane is 205 and 175 miles per hour.

Given information-

The distance between the planes is 380 miles.

The speed of the one plane is 30 miles per hour faster than other.

Both the planes travels the distance of 380 miles in 1 hour.

Relative speed

When the two bodies travel at the same direction, the relative speed of the two bodies is the sum of the speed of both the bodies.

Suppose the speed of the speed of the faster plane is x miles per hour, then the speed of the other plane is (x-30) miles per hour.

As both the plane covets the distance of 380 miles in one hour thus the relative speed of both the plane is 380 miles per hour.

By the definition of the relative speed,

[tex]\begin{aligned}\\ x+x-30&=380\\ 2x&=380+30\\ x&=\dfrac{410}{2}\\ x&=205\\ \end[/tex]

Thus the speed of the faster plane is 175. The other plane is 30 miles slower than the faster one. Thus the speed of the other plane is,

[tex]=205-30=175[/tex]

Thus the speed of the plane is 205 and 175 miles per hour.

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