Two teams are playing tug of war. team a pulls to the right with a force of 450 n. team b pulls to the left with a force of 415 n. what is the net force on the rope, and what is its direction?

Since the two teams are pulling away from each other with the given forces, the net force can be calculated by subtracting the forces.
team A - team B = 450 N - 415 N
= 35 N
Thus, net force on the rope is 35 N and the direction is towards A.

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facundo3141592 facundo3141592 · Answer 2 · 2019-11-25T21:33:27+01:00

Answer: the net force in the rope is 35N pointing right.

Explanation:

The total force applied on the string is equal to the sum of all the forces applied to it:

We know that both teams are pulling in different directions, so the forces have an opposite direction (and hence, opposite sign)

If we define the positive x-axis as the right; then we know that team A is pulling with a force of 450N

And team B is pulling with a force of -415N (because they are pulling to the left).

Then the total force is F = F1 + F2 = 450N - 415N = 35N

This means that the net force in the rope is 35N, and the direction is right (because it's positive)