This can be solved using the equation that the heat added to a substance equals the product of the mass of the substance, the specific heat of the substance, and the change in temperature. You may have seen this equation as Q=mCΔT
In order to use this equation, we need to identify what variables we know:
m = mass = 200. grams
C = specific heat of water = 4.184 Joules/g°C = 1 calorie/g°C
ΔT = T(final) - T(initial) = 25°C - 19°C = 6°C
Now we can plug in these values into the equation Q = mCΔT
Q = (200. grams) * (1 calorie/g°C) * (6°C) = 1200 calories of heat required
