3) The most common isotope of hydrogen contains a proton and an electron separated by amount 5.0•10^-11m. The mass of a proton is approximately 1.7•10^-27 kg. The mass of elections is approximately 9.0•10^-31kg.

I'm going to try this hopefully it'll translate from my phone, but the equations are almost exactly the same. The only difference is using mass instead of charges and the Gravitational constant instead of Coloumb's constant. Here we go...
F = (6.67×10^-11)*((1.7×10^-27)(9.0×10^-31)/(5.0×10^-11)^2)
F = (6.67×10^-11)*(1.53×10^-57/2.5×10^-21)
F = 4.082×10^-47

Answer Link

moya1316 moya1316 · Answer 2 · 2019-09-29T12:25:27+02:00

Answer:

This means that the electric force is approximately 10⁴⁰ times greater than the gravitational force.

Explanation:

In your case, you are asked to find the force of attraction due to the mass of the particles and that due to the electric charge.

a) Let us first calculate the force of attraction due to mass, using the law of universal gravitation

Fg = G m1 m2 / r²

With G the universal gravitation constant 6.672 10-11 N m2 / Kg2

For this calculation we have all the data, so we substitute in the equation

Fg = 6,672 10⁻¹¹ 1.7 10⁻²⁷ 9.0 10⁻³¹ / (5 10⁻¹¹)²

Fg = 4.08 10⁻⁻⁴⁷ N

b) Now we calculate the force due to the charges, using Coulomb's law

[tex]F_{e}[/tex] = k q1 q2 / r2

Where k is the Coulomb constant that is worth 8,987 109 N m2 / C2, q is the charge of each particle and r is the distance that separates it, this is the atomic radius

Fe = 8,987 10⁹ (1.6 10⁻¹⁹) (-1.6 10⁻¹⁹) / (5.0 10⁻¹¹)²

Fe = -9.20 10⁻⁷ N

The negative sign indicates that the force is attractive

c) To analyze the difference between the two forces, we divide their values

Fe / Fg = 9.2 10⁻⁷ / 4.08 10⁻⁴⁷

Fe / Fg = 2 10⁴⁰

This means that the electric force is approximately 10⁴⁰ times greater than the gravitational force.