Respuesta :
A = kdv^2 where A = amount oil d = distance and v = speed and k is a constant
so
30 = k*85*42^2
Now solve for k:-
k = 30 / (85*42^2) = 0.00020008
So when d = 26 and v = 54
Amount of oil A = 0.00020008 * 26*54^2
= 15.2 barrels
so
30 = k*85*42^2
Now solve for k:-
k = 30 / (85*42^2) = 0.00020008
So when d = 26 and v = 54
Amount of oil A = 0.00020008 * 26*54^2
= 15.2 barrels
The amount of oil used when the ship travels 26 miles at 54 mi/h is 15.2 barrels
Let the amount of oil used by the ship is [tex]y[/tex] barrels
let the distance traveled be [tex]s[/tex] miles
Let the velocity of the of the ship be [tex]v[/tex] miles per hour
then according to the given condition we can write equation (1)
[tex]y\; \alpha \; s\; v^2\\\\\\y\; = k \; s\; v^2....(1)\\\\\\rm where \; k = constant \; of\; Proportionality[/tex]
Given that ,
Quantity of Oil used by ship = 30 barrels
Speed of the Ship =42 miles per hour
Distance traveled by the ship = 85 miles
Putting these values in equation (1) we can get
[tex]\rm 30= k\times 85\times\ (42)^2\\k = 0.0002[/tex]
So the equation of amount of oil used can be written as equation (2)
[tex]y = 0.0002\times sv^2....(2)[/tex]
According to second condition given in the question we can write
[tex]\rm y = 0.0002\times 26\times (54)^2\\\rm y= 15.2 \; barrels[/tex]
For more information please refer to the link below
https://brainly.com/question/21328304
