Answer:
The function f(x)= [tex]x^2-12x+20[/tex] has zeroes at x=10 and x=2.
Step-by-step explanation:
Given the zeroes of the function at x=10 and x=2
x=10
x-10=0
x=2
x-2=0
Now , the factors of the function are (x-10) and (x-2)
The function can be obtain by multiplying these factors then we can write
f(x)=[tex](x-10)(x-2)[/tex]
f(x)=[tex]x(x-2)-10(x-2)[/tex]
f(x)=[tex]x^2-2x-10x+20[/tex]
f(x)=[tex]x^2-12x+20[/tex]
Hence, the function is f(x)=[tex]x^2-12x+20[/tex] and the zeroes of function at x=10 and x=2.
