A rectangle's length is 6 units greater than its width. Write an equation expressing the rectangle's area, A, as a function of w. A) A = 2w + 6 B) A = 4w + 12 C) A = w2 + 6w D) A = w2 + 12w

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length =width +6


Area=width × length



Area=w. (w+6)

Answer:

Option C is correct.

an equation expressing the rectangle's area , [tex]A = w^2+6w[/tex]

Step-by-step explanation

Area of rectangle(A) is given by:

[tex]A = lw[/tex]

where,

l is the length of the rectangle and w is the width of the rectangle.

As per the  statement:.

A rectangle's length is 6 units greater than its width

⇒[tex]l = 6+w[/tex]

Substitute in the above formula;a we have;

[tex]A = (6+w) \cdot w[/tex]

Using distributive property we have;

[tex]A = 6w+ w^2[/tex]

or

[tex]A = w^2+6w[/tex]

Therefore, an equation expressing the rectangle's area is, [tex]A = w^2+6w[/tex]