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N 80-kg man is one fourth of the way up a 10-m ladder that is resting against a smooth, frictionless wall. if the ladder has a mass of 20 kg and it makes an angle of 60 with the ground, find the force of friction of the ground on the foot of the ladder.

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My app says the force of friction is F = 340N
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The force of friction of the ground on the foot of the ladder is 170N.

How to calculate the force?

The force of friction of the ground on the foot of the ladder will be calculated thus:

Let AB = 20m

AC = 10 sin 60 = 8.6m

BC = 10 cos 60 = 5.0m

The force will be:

F × 8.66 = 80 × 9.8 × 5/4 + (20 × 9.8 × 2.5)

F × 8.66 = 980 + 490

F × 8.66 = 1470

F = 1470/8.66

F = 170N

The force is 170N.

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