Answer:
Area of a square(A) is given by:
[tex]A = s^2[/tex], where s is the side of the square.
Area of a triangle(A') is given by:
[tex]A' = \frac{1}{2} \cdot b \cdot h[/tex]
From the given figure:
Labelled the diagram shown below.
In a triangle ABC:
BC = 5 cm and FA =4 cm
then;
[tex]\text{A'} = \frac{1}{2} \cdot \text{BC} \cdot \text{FA}[/tex]
Substitute the given values we have;
[tex]A' = \frac{1}{2} \cdot 5 \cdot 4 =5 \cdot 2= 10 cm^2[/tex]
Now, find the area of square BCDE:
Side of the square BCDE (s)= 5 cm
then;
[tex]A = (5)^2 = 25 cm^2[/tex]
Then the area of the given composite figure :
[tex]A+A' = 25+10 = 35 cm^2[/tex]
Therefore, the area of the given figure is, [tex]35 cm^2[/tex]
