On the first day of a measles outbreak at a school, 5 students were identified to have the measles. Each day for the following two weeks, the number of new cases doubled from those identified with the disease the day prior.

How many students are identified to have measles in all at the end of the 6th day of the outbreak?



286

315

345

378

Respuesta :

If you interpret the question as is, the answer is in the thousands, which is not listed. The last part of the question should read 'the number of new cases doubled from those newly identified cases from the day prior. The question is very poorly phrased.

Day 1 : 5
Day 2: 5 + 10
Day 3: 15 + 20
Day 4: 35 + 40
Day 5: 75 + 80
Day 6: 155 + 160

Which is 315 at the end of 6th day

The number of students which are identified to have measles in all at the end of the 6th day of the outbreak are 315.

What is geometric sequence?

Geometric sequence is the sequence in which the next term is obtained by multiplying the previous term with the same number for the whole series.

The sum of nth term for geometric sequence is find out with following formula.

[tex]S_n=\dfrac{a(1-r^n)}{1-r}[/tex]

Here, (a) is the first term of the sequence and (r) is the common ratio.

On the first day of a measles outbreak at a school, 5 students were identified to have the measles.

Each day for the following two weeks, the number of new cases doubled from those identified with the disease the day prior.

[tex]S_6=\dfrac{5(1-2^6)}{1-2}\\S_6=\dfrac{5(1-64)}{-1}\\S_6=\dfrac{5(-63)}{-1}\\S_6=315[/tex]

Thus, the number of students which are identified to have measles in all at the end of the 6th day of the outbreak are 315.

Learn more about the geometric sequence here;

https://brainly.com/question/1509142

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