The population of a type of local bass can be found using an infinite geometric series where a1 = 94 and the common ratio is one third. Find the sum of this infinite series that will be the upper limit of this population.

Respuesta :

a/(1-r)


a = 94

r = 1/3

94/(1-1/3)

= 141

Answer:

The sum of this infinite series that will be the upper limit of this population is, 141

Step-by-step explanation:

Formula for infinite  geometric series is given by:

[tex]S = \frac{a_1}{1-r}[/tex]        ....[1]

where,

[tex]a_1[/tex] is the first term,

r is the common ratio term.

As per the statement:

The population of a type of local bass can be found using an infinite geometric series where:

[tex]a_1 = 94[/tex]

[tex]r = \frac{1}{3}[/tex]

To find the sum of this infinite series that will be the upper limit of this population.

Substitute the given values in [1] we have;

[tex]S = \frac{94}{1-\frac{1}{3}} = \frac{94}{\frac{2}{3}} = 94 \cdot \frac{3}{2} = 47 \cdot 3 = 141[/tex]

Therefore, 141 is the sum of this infinite series that will be the upper limit of this population.