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PLEASE HELP!!
A line passes through(3,-2) and (6,2)
Write the equation for the line in point-slope form and rewrite the equation in slope-intercept form
A.y-3=4/3(x+2);-4x+3y=17
B.y+2=4/3(x+3);4x+3y=-18
C.y+2=4/3(x-3);-4x+3y=-18
D.y-2=4/3(x-3);4x+3y=18

Respuesta :

ghanami
Hello:
let  A(3,-2) and  B (6,2)
The slope is : a =  (YB -YA)/(XB -XA)
a = (2-(-2))/(6-3)
a =4/3
C)     .y+2=4/3(x-3);-4x+3y=-18 
because :  A(3,-2) : -2+2=4/2(3-3)  ...... 0=0    
                 B (6,2) : 2+2 =4/3(6-3)  .... 4 = 4

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