Answer:
d. [tex]16a^2b^2[/tex]
Step-by-step explanation:
Given expression,
[tex](\frac{1}{4ab})^{-2}[/tex]
[tex]=((4ab)^{-1})^{-2}[/tex] [tex]\because \frac{1}{a^m}=a^{-m}[/tex]
[tex]=(4ab)^{-1\times -2}[/tex] [tex]\because (a^m)^n=a^{mn}[/tex]
[tex]=(4ab)^2[/tex]
[tex]=(4)^2(a)^2(b)^2[/tex] [tex]\because (ab)^m=a^mb^m[/tex]
[tex]=16a^2b^2[/tex]
Hence, option d is correct.
