A positive charge of 2.3 x 10-5 C is located 0.58 m away from another positive charge of 4.7 × 10- C. What is the electric force between the two charges?
A. 2.13 N
B. 2.89 N
C. 1.68 N
D. 3.41 N

Respuesta :

The electric force between two charges can be calculated using Coulomb's law:

F = k * (|q1| * |q2|) / r^2

where F is the electric force, k is the electrostatic constant (k = 8.99 × 10^9 N m^2/C^2), |q1| and |q2| are the magnitudes of the charges, and r is the distance between the charges.

Given:
|q1| = 2.3 × 10^-5 C
|q2| = 4.7 × 10^-5 C
r = 0.58 m

Substituting the values into Coulomb's law, we have:

F = (8.99 × 10^9 N m^2/C^2) * (|2.3 × 10^-5 C| * |4.7 × 10^-5 C|) / (0.58 m)^2

Calculating this expression, we find:

F ≈ 2.89 N

Therefore, the electric force between the two charges is approximately 2.89 N. The correct option is B. 2.89 N.

I hope this helps! :)