To solve the compound inequality 2y + 3 ≥ -9 or -3y < -15, we'll solve each inequality separately and then combine the solutions.
First, let's solve the first inequality: 2y + 3 ≥ -9.
Subtract 3 from both sides:
2y ≥ -12
Divide both sides by 2 (note that dividing by a positive number does not change the inequality direction):
y ≥ -6
Next, let's solve the second inequality: -3y < -15.
Divide both sides by -3 (remember to reverse the inequality direction when dividing by a negative number):
y > 5
Now, let's combine the solutions. We have y ≥ -6 or y > 5.
In interval notation, we can express the solution as (-∞, -6] ∪ (5, ∞). This means that the solution includes all real numbers less than or equal to -6, as well as all real numbers greater than 5.
