Respuesta :
The electron donor in the reaction is the Zn and as a result it is oxidised to Zn²⁺. A move from an oxidation state of 0 to 2 (Oxidation is the Loss of Electron)
Answer: Zinc element was the electron donor
Explanation:
[tex]Zn(s)+Cu+2(aq)\rightarrow Zn^{+2}(aq)+Cu(s)[/tex]
In the given reaction, the zinc metal is getting oxidized to zinc ion by loosing 2 electrons and copper ion are getting reduced to copper by gaining 2 electrons.
[tex]Zn\rightarrow Zn^{2+}+2e^-[/tex]
[tex]Cu^{2+}+2e^-\rightarrow Cu[/tex]
So, in the given reaction zinc is an element which donates its electrons.Hence, electron donor was the zinc element.