Respuesta :
So let's plug in the values:
[tex](8*4-2)10\div(2+4)[/tex]
Brackets/Parentheses are the highest priority.
Looking in the first set of brackets:
We need to prioritize the multiplication above the division.
So first multiplying,
[tex](32-2)10\div(2+4)[/tex]
then subtracting,
[tex](30)10\div(2+4)[/tex]
then moving to the other parentheses, applying the addition,
[tex](30)10\div(6)[/tex]
Ok we dealt with everything INSIDE of the brackets, so let's drop our brackets remembering that the 30 and 10 are multiplying.
[tex]30\times10\div6[/tex]
Apply multiplication/division from left to right.
So first multiply,
[tex]300\div6[/tex]
Then finally, divide,
[tex]50[/tex]
Hope that makes sense!
[tex](8*4-2)10\div(2+4)[/tex]
Brackets/Parentheses are the highest priority.
Looking in the first set of brackets:
We need to prioritize the multiplication above the division.
So first multiplying,
[tex](32-2)10\div(2+4)[/tex]
then subtracting,
[tex](30)10\div(2+4)[/tex]
then moving to the other parentheses, applying the addition,
[tex](30)10\div(6)[/tex]
Ok we dealt with everything INSIDE of the brackets, so let's drop our brackets remembering that the 30 and 10 are multiplying.
[tex]30\times10\div6[/tex]
Apply multiplication/division from left to right.
So first multiply,
[tex]300\div6[/tex]
Then finally, divide,
[tex]50[/tex]
Hope that makes sense!
x=10, y=4, and z=2
(8y-2)x ÷ (z+y)
Plug in the x values, as well as the y and z values.
(8(4)-2)) (10) ÷ (2+4)
Simplify.
(32-2) (10) ÷ (6)
Simplify.
(30) (10) ÷ 6
Simplify.
300 ÷ 6
Your answer is:
c) 50
~Hope I helped!~
(8y-2)x ÷ (z+y)
Plug in the x values, as well as the y and z values.
(8(4)-2)) (10) ÷ (2+4)
Simplify.
(32-2) (10) ÷ (6)
Simplify.
(30) (10) ÷ 6
Simplify.
300 ÷ 6
Your answer is:
c) 50
~Hope I helped!~