Respuesta :

So let's plug in the values:

[tex](8*4-2)10\div(2+4)[/tex]

Brackets/Parentheses are the highest priority.
Looking in the first set of brackets:
We need to prioritize the multiplication above the division.
So first multiplying,

[tex](32-2)10\div(2+4)[/tex]

then subtracting,

[tex](30)10\div(2+4)[/tex]

then moving to the other parentheses, applying the addition,

[tex](30)10\div(6)[/tex]

Ok we dealt with everything INSIDE of the brackets, so let's drop our brackets remembering that the 30 and 10 are multiplying.

[tex]30\times10\div6[/tex]

Apply multiplication/division from left to right.
So first multiply,

[tex]300\div6[/tex]

Then finally, divide,

[tex]50[/tex]

Hope that makes sense!
cher
x=10, y=4, and z=2

(8y-2)x ÷ (z+y)

Plug in the x values, as well as the y and z values.

(8(4)-2)) (10) ÷ (2+4)

Simplify.

(32-2) (10) ÷ (6)

Simplify.

(30) (10) ÷ 6

Simplify.

300 ÷ 6

Your answer is: 

c) 50

~Hope I helped!~