A sample of propane (C3H8) has a mass of 0.47 g. The sample is burned in a bomb calorimeter that has a mass of 1.350 kg and a specific heat of 5.82 J/(g • °C). How much energy is released by the reaction if the temperature of the calorimeter rises by 2.87°C?

Respuesta :

Heat gained or released by a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:

Heat = mC(T2-T1)
Heat = 1350 (5.82) (2.87)
Heat = 22549 J or 22.55 kJ

The energy that is released by the reaction if the temperature of the calorimeter rises by 2.87°C is calculated by the formula Q=mcΔT.

What is Specific heat?

Specific heat is the amount of heat required to raise the temperature of one gram of a substance by one Celsius degree.

The energy released in a chemical reaction is calculated as,

Q=mcΔT

Q=1350×5.82×2.87

Q= 22,549 J or 22.55 KJ

where 'Q' is the heat energy released in a chemical reaction

           'm' is the mass of the sample (in g)

            'c' is the specific heat (in joule per kg degree Celcius)

          'ΔT' is the change in temperature (in degree Celcius).

Therefore, the energy that is released by the reaction if the temperature of the calorimeter rises by 2.87°C is 22,549 J or 22.55 KJ.

To learn more about Specific heat, refer to the link:

https://brainly.com/question/13439286