A box contains 10 ​transistors, 3 of which are defective. If 3 are selected at​ random, find the probability that a. All are defective. b. None are defective.

Respuesta :

3/10(2/9)(1/8)

3/10(3/9)(3/8)
a) 3/10 x 2/9 x 1/8= 1/120

b) 1-1/120=119/120