and0013
contestada

A chemical manufacturer wishes to obtain 700 litres of a 24% acid solution by mixing a 40% acid solution with a 15% solution. How many litres of each solution should be used?

Respuesta :

00 x 0.24 = a x 0.40 + ( 700 -a ) x 0.15 = 0.40 a - 0.15 a + 105.00 
168.00 = 0.25a + 105.00 
a = 252 
Solution with 40% ....................252 liters........................ans 

Solution with 15 % ...................700 - 252= 448 liters.........................ans

Litres of 40 percentage solution is equals to 252litres and litres of 15percentage solution is equals to 448litres.

What is percentage?

" Percentage is defined as the hundredth part of a given  number."

According to the question,

Given,

Total litres of solution = 700litres

Percentage of acid solution = 24%

'x' represents the 40% of acid solution

'700-x' represents the 15% of solution

Substitute the value as per given condition we get,

[tex]24\% of 700 = 40\% of x + 15\%of (700 -x)\\\\\implies \frac{24}{100} (700)= \frac{40}{100}(x) +\frac{15}{100}(700-x)\\ \\ \implies 16800= 40x+10500-15x\\\\\implies 6300 =25x\\\\\implies x= \frac{6300}{25}\\ \\\implies x= 252litres[/tex]

Therefore,

40 percentage of acid solution = 252litres

And 15percentage of solution is

[tex]700-252 = 448litres[/tex]

Hence , litres of 40 percentage solution is equals to 252litres and litres of 15percentage solution is equals to 448litres.

Learn more about percentage here

https://brainly.com/question/14979505

#SPJ3