Respuesta :
2a+3c=61
2a=61-3c
a=30.5-1.5c
...
3a+5c=96, using a found above we get:
3(30.5-1.5c)+5c=96
91.5-4.5c+5c=96
91.5+0.5c=96
0.5c=4.5
c=9, and since a=30.5-1.5c
a=17
So adult tickets cost £17.00 and child tickets cost £9.00
2a=61-3c
a=30.5-1.5c
...
3a+5c=96, using a found above we get:
3(30.5-1.5c)+5c=96
91.5-4.5c+5c=96
91.5+0.5c=96
0.5c=4.5
c=9, and since a=30.5-1.5c
a=17
So adult tickets cost £17.00 and child tickets cost £9.00
The price of the ticket for an adult is £14.34 and the price of the ticket for a child is £9 and this can be determine by forming the linear equation in two variables.
Given :
- The smith family of two adults and three chidren pays £61.
- The jones family of three adults and five children pay £96.
Linear equation has to be form to determine the price of the ticket for an adult and a child.
Let 'a' be the price of ticket for an adult and 'c' be the price of ticket for a child than the linear equations will be:
2a + 3c = 61 --- (1)
3a + 5c = 96 --- (2)
Now, from equation (1) solve for 'a'.
[tex]\rm a = \dfrac{61-3c}{2}[/tex] ---- (3)
Now, put the value of 'a' obtain in equation (3) in eqaution (2).
[tex]3\times\left(\dfrac{61-3c}{2}\right)+5c = 96[/tex]
[tex]183-9c+10c=192[/tex]
c = £ 9
Now, put the value of 'c' in equation(3).
[tex]a = \dfrac{61-(2\times9)}{3}[/tex]
a = £ 14.34
Therefore, the price of the ticket for an adult is £14.34 and the price of the ticket for a child is £9.
For more information, refer the link given below:
https://brainly.com/question/12420841