Answer:
[tex]{IrPO_4}^.H_2O[/tex]
Explanation:
Hello,
In this case, iridium (III) cation is represented by [tex]Ir^{+3}[/tex] and phosphate anion is represented by [tex](PO_4)^{-3}[/tex]. In such a way, the required formula turns out into:
[tex]{IrPO_4}^.H_2O[/tex]
By considering that this is about a monohydrate so it has one additional water molecule in its structure.
Best regards.
