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The number of bacteria N­ at a certain time t is given by N = 100et /10, when there are 100 bacteria at time t = 0 hours. Find how many hours t it takes for the bacteria to double (that is, increase from 100 to 200 bacteria). [Use either ln(2) ≈ 0.7 to approximate your answer as appropriate.]

Respuesta :

irspow
I assume you meant N=100e^(t/10) so

200=100e^(t/10)

2=e^(t/10)  taking the natural log of both sides

ln2=t/10

t=10ln2

t≈6.93 hours

check...

N=100e^(.693)≈200

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