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You are standing on a ladder, helping with some repairs at home. You drop a hammer and it hits the floor at a speed of 4 feet per second. If the acceleration due to gravity (g) is 32 feet/second^2 , how far above the ground (h) was the hammer when you dropped it? Use the formula

V= square root 2gh


A. 16.0 feet
B. 1.0 foot
C. 0.25 feet
D. 0.5 feet

You are standing on a ladder helping with some repairs at home You drop a hammer and it hits the floor at a speed of 4 feet per second If the acceleration due t class=

Respuesta :

j4cek
[tex]h=\dfrac{v^2}{2g}=\dfrac{4^2}{2\cdot 32}=\dfrac{16}{64}=\dfrac{1}{4}=0.25[/tex]
Answer: C 0.25 feet.

Answer:

C 0.25Ft

Step-by-step explanation:

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