Respuesta :
If you meant a thickness of 1/2 inch. . .
Because the inserts are put on all the sides, the dimensions of the usable space are 5 X 5 X 9. This means the diameter of the base is 5. The radius is half the diameter, so we divide 5 by 2 to get the radius. 5/2 = 2.5. Now, we plug in the radius and the height (9) into the formula for the volume of a cylinder, which is [tex]volume= \pi r^{2} h[/tex]
[tex]v= \pi 2.5^{2} *9=176.6 inches^{3} [/tex]
So, D is correct.
Because the inserts are put on all the sides, the dimensions of the usable space are 5 X 5 X 9. This means the diameter of the base is 5. The radius is half the diameter, so we divide 5 by 2 to get the radius. 5/2 = 2.5. Now, we plug in the radius and the height (9) into the formula for the volume of a cylinder, which is [tex]volume= \pi r^{2} h[/tex]
[tex]v= \pi 2.5^{2} *9=176.6 inches^{3} [/tex]
So, D is correct.
The volume of the largest candle that can be shipped out is 176.6 in³ if the boxes measure 6 in. by 6 in. by 10 in option (D) is correct.
What is a cylinder?
In geometry, it is defined as the three-dimensional shape having two circular shapes at a distance called the height of the cylinder.
We have:
The boxes measure 6 in. by 6 in. by 10 in.
As we know, the volume of the cylinder is given by:
[tex]\rm V =\pi \times h\times r^2[/tex]
The diameter = 6 -(1/2) - (1/2) = 5 in
The radius r = 5/2 = 2.5 in
The height h = 10-(1/2) - (1/2) = 9 in
The volume of the largest candle that can be shipped out is:
[tex]\rm V =\pi \times 9\times (2.5)^2[/tex]
V = 176.6 in³
Thus, the volume of the largest candle that can be shipped out is 176.6 in³ if the boxes measure 6 in. by 6 in. by 10 in option (D) is correct.
Learn more about the cylinder here:
brainly.com/question/3216899
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