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The length can be found using the Pythagorean Theorem...

c^2=a^2+b^2 and in this case:

d^2=(dx^2)+(dy^2)

d^2=(3-7)^2+(12-9)^2

d^2=-4^2+3^2

d^2=16+9

d^2=25

d=5 

So the length of AB=5 units.

The distance between two points A and B is 5 units.

What is the distance between two points on a plane?

If two points with their coordinates are mentioned, then we can easily find the distance between those two points.

Let, (x₁, y₁) and (x₂, y₂) are two points on a plane.

Therefore, the distance between them is:

√[(x₂ - x₁)² + (y₂ - y₁)²] units.

Given, two points are A = (7, 9) and B = (3, 12).

Therefore, distance between point A and point B is:

AB = √[(3 - 7)² + (12 - 9)²] units

= √[16 + 9] units.

= √[25] units.

= 5 units                     (As distance can't be negative.)

Learn more about distance between two points here: https://brainly.com/question/14732100

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