Answer: [tex]-43^{\circ} C[/tex]
Explanation:
We can solve the problem by using Charle's law, which states that for a gas at constant pressure, the volume V and the absolute temperature of the gas T are directly proportional. In formulas:
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
where
[tex]V_1 = 65 mL=0.065 L[/tex] is the initial volume
[tex]T_1 = 325 C=598 K[/tex] is the initial temperature
[tex]V_2 = 25 mL=0.025 L[/tex] is the final volume
[tex]T_2[/tex] is the final temperature
By solving the equation,
[tex]T_2 = T_1 \frac{V_2}{V_1}=(598 K)\frac{0.025 L}{0.065 L}=230 K[/tex]
In Celsius, the final temperature is
[tex]T_2 = 230 K-273 = -43^{\circ} C[/tex]
