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A car traveling at 60 km/h will skid 30 m when its brakes are locked. if the same care is traveling at 180 km/h, what will be the skidding distance? be sure to show all work to support your answer.

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The first car travels at 60km/h and skid at 30m away from the starting point while another car is also traveling at 180km/h. Now, we need to solve for the skidding distance.
We assigned variables such as:
V1=60km/h
V2=180km/h
Skid1=30m
Skid2=?
We solve this by ratio and proportion method such as shown below:
V1/V2=skid1/skid2
60/180=30/skid2
skid2=(30*180)/60
skid2=90meters

Th answer is 90 meters.

Answer:

The car skidding distance would be 270 m

Explanation:

Given that,

Speed of car = 60 km/h

Skid distance = 30 m

Another speed of car =  180 km/h

Using motion equation:

[tex]v^2-u^2=2as[/tex]

The square of speed is proportional to the distance.

Thus. [tex]v^2\propto s[/tex]

The ratio of the speed of the both cars

[tex]\dfrac{V_2^2}{V_1^2}=\dfrac{S_2}{S_1}[/tex]

[tex]V_1=60[/tex]

[tex]V_2=180[/tex]

[tex]S_1=30[/tex]

[tex]S_1=d[/tex]

Substitute the value into formula

[tex]\dfrac{180^2}{60^2}=\dfrac{d}{30}[/tex]

[tex]9\times 30 = d[/tex]

[tex]d=270\ m[/tex]

Hence, The car skidding distance would be 270 m

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