[tex] \rho = \frac{m}{V}[/tex]
where ρ is the density, m is the mass, and V is the volume.
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We have
v = 60
m = 1320
[tex]\rho =?[/tex]
[tex]\rho = \frac{m}{V} \\\\\rho = \frac{1320}{60}\\\\\rho = 22[/tex]
The density of the pile is 22 kg/cf