Answer: The mass of [tex]H_2O[/tex] formed will be [tex]4.95\times 10^{-3}[/tex] grams
Explanation:
For the given reaction:
[tex]NaOH+HCl\rightarrow NaCl+H_2O[/tex]
By Stoichiometry of the reaction:
1 mole of NaCl produces 1 mole of water molecule.
So, [tex]2.75\times 10^{-4}mol[/tex] of NaCl will produce [tex]2.75\times 10^{-4}mol[/tex] of [tex]H_2O[/tex]
To calculate the mass of water, we will use the equation used to calculate number of moles, which is:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Number of moles of [tex]H_2O=2.75\times 10^{-4}[/tex] moles
Molar mass of water = 18 g/mol
Putting values in above equation, we get:
[tex]2.75\times 10^{-4}mol=\frac{\text{Given mass}}{18g/mol}\\\\\text{Given mass of water}=4.95\times 10^{-3}g[/tex]
Hence, the mass of [tex]H_2O[/tex] formed will be [tex]4.95\times 10^{-3}[/tex] grams
